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# How do we subtract using surds and integers? watch

1. Ie: Is it possible to simplify:

/sqrt(3) - 1

??

Or do I just leave it that way (surd of root 3, minus 1) ?

Thanks

Edit: I'd like the answer to the equation to be exact, not rounded, hence the question Merci!
2. That is fully simplified.
3. (Original post by Mr M)
That is fully simplified.
Thank you!

So how do I write the complex number z = (1 - i)(sqrt3 - i) in polar exponential form? (this question is for anyone that knows)

I've simplified the complex number to: z = -sqrt3 - 1
I have (principal) argz of -pi/2
And I've written it as: (-root3 - 1)e-[(pi)i/2]
But this looks a little wrong/complicated to be the final answer :/
4. Yep...you can't simplify any further.
5. (Original post by PhysicsGal)
Thank you!

So how do I write the complex number z = (1 - i)(sqrt3 - i) in polar exponential form? (this question is for anyone that knows)

I've simplified the complex number to: z = -sqrt3 - 1
I have (principal) argz of -pi/2
And I've written it as: (-root3 - 1)e-[(pi)i/2]
But this looks a little wrong/complicated to be the final answer :/

Ahh nevermind, I expanded the 2 brackets incorrectly (I did 1*sqrt3 = 1, instead of = sqrt3).

The final answer is now (2sqrt2)e-[(5pi)i/12]

​Thanks y'all!
6. (Original post by PhysicsGal)
Ahh nevermind, I expanded the 2 brackets incorrectly (I did 1*sqrt3 = 1, instead of = sqrt3).

The final answer is now (2sqrt2)e-[(5pi)i/12]

​Thanks y'all!
Note that you could have spotted that your original answer was not correct because when you do write a complex number in the form you want the modulus r to be POSITIVE
7. (Original post by davros)
Note that you could have spotted that your original answer was not correct because when you do write a complex number in the form you want the modulus r to be POSITIVE
Kudos! ^^

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