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How do we subtract using surds and integers? Watch

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    Ie: Is it possible to simplify:

    /sqrt(3) - 1

    ??

    Or do I just leave it that way (surd of root 3, minus 1) ?

    Thanks

    Edit: I'd like the answer to the equation to be exact, not rounded, hence the question Merci!
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    That is fully simplified.
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    (Original post by Mr M)
    That is fully simplified.
    Thank you!

    So how do I write the complex number z = (1 - i)(sqrt3 - i) in polar exponential form? (this question is for anyone that knows)

    I've simplified the complex number to: z = -sqrt3 - 1
    I have (principal) argz of -pi/2
    And I've written it as: (-root3 - 1)e-[(pi)i/2]
    But this looks a little wrong/complicated to be the final answer :/
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    Yep...you can't simplify any further.
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    (Original post by PhysicsGal)
    Thank you!

    So how do I write the complex number z = (1 - i)(sqrt3 - i) in polar exponential form? (this question is for anyone that knows)

    I've simplified the complex number to: z = -sqrt3 - 1
    I have (principal) argz of -pi/2
    And I've written it as: (-root3 - 1)e-[(pi)i/2]
    But this looks a little wrong/complicated to be the final answer :/

    Ahh nevermind, I expanded the 2 brackets incorrectly (I did 1*sqrt3 = 1, instead of = sqrt3).

    The final answer is now (2sqrt2)e-[(5pi)i/12]


    ​Thanks y'all!
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    (Original post by PhysicsGal)
    Ahh nevermind, I expanded the 2 brackets incorrectly (I did 1*sqrt3 = 1, instead of = sqrt3).

    The final answer is now (2sqrt2)e-[(5pi)i/12]


    ​Thanks y'all!
    Note that you could have spotted that your original answer was not correct because when you do write a complex number in the form re^{i\theta} you want the modulus r to be POSITIVE
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    (Original post by davros)
    Note that you could have spotted that your original answer was not correct because when you do write a complex number in the form re^{i\theta} you want the modulus r to be POSITIVE
    Kudos! ^^
 
 
 
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