I've uploaded my work so far
I've got work out the probability that at least two of the witnesses select the accused. I know I could do this by working it all out manually, was just wondering if there was a quicker way to do it?
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(MEI S1 - Probability) Stuck on exercise question watch
- Thread Starter
- 25-03-2013 09:14
- 25-03-2013 09:46
Since the probability for each witness selecting an accused is the same across all 3 witnesses, the shortest way imo would be to use your knowledge of binomial distributions, but in this case n=3 that probably doesn't even count as a simplification.
Just how much work are you talking about when you say "manually"?
You've already found out the probability of 3 correct P(3 correct), and P(≥2 correct) is just P(2 correct) + P(3 correct).Last edited by aznkid66; 25-03-2013 at 09:48.