I've worked out the order of both reactants as first order.
The reactions are:
1) S2O82- (aq) + 2I- (aq) --> 2SO42- (aq) + I2 (aq)
2) 2S2O32- (aq) + I2 (aq) --> S4O62- (aq) + 2I- (aq)
And I know the RDS lies within reaction 1 – otherwise the reaction wouldn’t work, as no iodine would be produced. However, there must be another step, as 2 moles of I- can’t be used...
I NEED URGENT HELP PLEASE!
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Reaction Mechanism for iodide and peroxodisulfate watch
- Thread Starter
- 25-03-2013 17:50
- 17-02-2015 12:01
- 23-02-2015 17:16