Reaction Mechanism for iodide and peroxodisulfate

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drahc
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Hi Guys,

I've worked out the order of both reactants as first order.

The reactions are:

1) S2O82- (aq) + 2I- (aq) --> 2SO42- (aq) + I2 (aq)
2) 2S2O32- (aq) + I2 (aq) --> S4O62- (aq) + 2I- (aq)

And I know the RDS lies within reaction 1 – otherwise the reaction wouldn’t work, as no iodine would be produced. However, there must be another step, as 2 moles of I- can’t be used...

I NEED URGENT HELP PLEASE!
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Mona17ta
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hj2324
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possibilities for 1st order for iodide that i have found are

from HERE

S2O8^-2 +I- --> SO4^2- +SO4I- slow rate determining step
SO4I- + I- --> SO4^2- +I2 fast

OR FROM HERE

I- + S2O8 2- --> *[I...S2O8]3- SLOW RDS

*[I...S2O8]3- + I- --> I2 + 2 SO4 2-
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