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# integrating 2^t watch

1. (Original post by cera ess six)
I know how to differentiate/integrate it reverse chain rule way.

F'(t) = 2^t ln2

Then using reverse chain rule you get 2^t/ln2

Its just the other methods of doing it I dont understand
Which other methods?
2. (Original post by Mr M)
Well this is exactly the same. ln 2 is just the constant a.

1/ln2 e^xln2 ?
3. (Original post by cera ess six)
1/ln2 e^xln2 ?
And that is the answer you were seeking.
4. (Original post by Mr M)
And that is the answer you were seeking.
I thought no matter what integration method I use I would end up at exactly 2^t/ln2. Thanks so much.
5. (Original post by cera ess six)
I thought no matter what integration method I use I would end up at exactly 2^t/ln2. Thanks so much.
Clearly you must as the result of integration does not change (with the exception of the constant of integration) depending on the method you select.

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