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    Hi I am stuck on a question
    The first part says draw the graphical formula of two alekenes formed when pentan-2-ol is heated with conc. sulphuric acid.
    I have drawn Pent-1-ene and Pent-2-ene
    Is this correct?

    The next one is state the type of reaction taking place in a ii.
    I put Elimination.

    And the one I am stuck on is:
    Explain why the type of reaction taking place in a ii does not occur when 2,2-dimethylpropan-1-ol is heated with conc. sulphuric acid... HELP!:confused:
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    I'd say because it was a primary alcohol, along with the fact that you have the two methyl groups, the double bond required to create an alkene would be unable to form.
 
 
 
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