Hi I am stuck on a question
The first part says draw the graphical formula of two alekenes formed when pentan-2-ol is heated with conc. sulphuric acid.
I have drawn Pent-1-ene and Pent-2-ene
Is this correct?
The next one is state the type of reaction taking place in a ii.
I put Elimination.
And the one I am stuck on is:
Explain why the type of reaction taking place in a ii does not occur when 2,2-dimethylpropan-1-ol is heated with conc. sulphuric acid... HELP!
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- Thread Starter
- 26-03-2013 18:03
- 26-03-2013 20:20
I'd say because it was a primary alcohol, along with the fact that you have the two methyl groups, the double bond required to create an alkene would be unable to form.