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    voltage.docx

    I need help on both bi and biv. The mark scheme answers don't make sense for me and I need some explanations.

    Thanks
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    Bulb 1 is at its rated value and the voltmeter is connected across it directly so it must read 12v.

    12v + the PD across the resistor must add up to 15 (Kirchoff2) so the PD across the resistor must be 15-12 = 3v
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    (Original post by teachercol)
    Bulb 1 is at its rated value and the voltmeter is connected across it directly so it must read 12v.

    12v + the PD across the resistor must add up to 15 (Kirchoff2) so the PD across the resistor must be 15-12 = 3v
    But the voltmeter is connected directly across lamp B as well as lamp A. This is so hard to understand for me .

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    Lamp B has a resistor in series with it so the PD across this resistor + PD across lamp B is 12v
 
 
 
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