Titration Curve of HClwith NaOH (0.1035 M) as Titrant
The equivalence point was reached when about 31.43 ml NaOH was added. This means 3.25 x 10-3moles of NaOH were needed to react with 3.0 x 10-3moles of HCl.
How, what formula must be used?
What equation do I need to use? Watch
- Thread Starter
- 27-03-2013 02:09
- 27-03-2013 04:57
what are you trying to find out anyway?