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    Titration Curve of HClwith NaOH (0.1035 M) as Titrant
    The equivalence point was reached when about 31.43 ml NaOH was added. This means 3.25 x 10-3moles of NaOH were needed to react with 3.0 x 10-3moles of HCl.

    How, what formula must be used?
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    what are you trying to find out anyway?
 
 
 
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