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    Please help me answer these questions.
    First here is my graph - http://www.imagebam.com/image/328fcb245661205We used 50ml of phosphorus acid, and titrated 0.1M NaOH solution.
    The first bit asks from the volume of NaOH added, and its concentration, calculate the number of moles of NaOH consumed at each equivalence point, I found two on the graph, them bring 9.0ml and 18.02ml. I thought moles = mass / molar mass.

    Next calculate number of moles of phosphoric acid consumed at the end point and therefore the concentration of the phosphonic/phosphorus solution given.

    Thank you
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    number of moles= concentration x volume however you must make sure the volume is in dm3

    1ml=1cm3
    1dm3=1000cm3
    so 9ml = 0.009dm3
 
 
 
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Updated: March 27, 2013

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