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    So I've worked through a paper have a few things I couldn't do.

    The last bit of question 9. So I have found the values needed and it comes out as needing to find the Phi of (3.494)- Phi of (-1.655).
    The problem is in the normal tables it doesn't go up to the phi of 3.494...

    http://www.ocr.org.uk/Images/78550-q...atistics-2.pdf


    Thanks.
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    (Original post by Music99)
    So I've worked through a paper have a few things I couldn't do.

    Question 5, I think it's Binomial distributed, but I got the wrong answer.

    And the last bit of question 9. So I have found the values needed and it comes out as needing to find the Phi of (3.494)- Phi of (-1.655).
    The problem is in the normal tables it doesn't go up to the phi of 3.494...

    http://www.ocr.org.uk/Images/78550-q...atistics-2.pdf


    Thanks.
    Use your answers to the first part of the question and use Poisson to estimate Binomial.
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    (Original post by Lunch_Box)
    Use your answers to the first part of the question and use Poisson to estimate Binomial.
    I meant the very first part of question 5 sorry. I had another look but I'm slightly confused I know it's Binomial so I can use the formula for calculating exactly equal to four, but I'ma bit unsure on which parameter to take for n and p in this case.
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    (Original post by Music99)
    I meant the very first part of question 5 sorry. I had another look but I'm slightly confused I know it's Binomial so I can use the formula for calculating exactly equal to four, but I'ma bit unsure on which parameter to take for n and p in this case.
    You can use the binomial formula then I'm guessing.

    P(girl) = 12/20
    P(boy) = 8/20
    n = 6
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    (Original post by Lunch_Box)
    You can use the binomial formula then I'm guessing.

    P(girl) = 12/20
    P(boy) = 8/20
    n = 6
    Ahh right makes sense. But then i'm a bit unsure on the bit with it saying more then one person can win a prize, doesn't that affect the calculation?
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