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    (Original post by Lunch_Box)
    Figure 2 shows a circle of radius 12 cm which passes through the points P and Q.
    The chord PQ subtends an angle of 120° at the centre of the circle.
    (a) Find the exact length of the major arc PQ. (2)
    (b) Show that the perimeter of the shaded minor segment is given by
    k(2π + 3 3 ) cm, where k is an integer to be found. (4)
    (c) Find, to 1 decimal place, the area of the shaded minor segment as a percentage
    of the area of the circle.


    for part c:




    I am unsure why the answer has given the total area of the circle as pi*12^2 rather than 2pi*12^2?
    Formula for area of circle = pi*r2
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    (Original post by joostan)
    Formula for area of circle = pi*r2
    Oh ffs i was thinking the forumla was theta*r^2
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    (Original post by Lunch_Box)
    Oh ffs i was thinking the forumla was theta*r^2
    lol dw everyone has their moments
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    can you please help me with part c.
    The arc AB of a circle, centre O and radius r cm, is such that angle AOB = 0.5 radians.

    Given that the perimeter of the minor sector of AOB = 30cm:
    a) calculate the value of r- (the radius is 12)
    b)show that the area of the minor sector AOB is 36cm^2
    c) Calculate the area of the segment enclosed by the chord AB and the minor arc AB
 
 
 
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