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HELP - Computer Mathematics Induction

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Original post by mos182
How? :s-smilie: Sorry for all the questions, just want to understand how you came about your answers


Sn=1(12n)1\displaystyle S_n=\frac{1(1-2^n)}{-1}

=12n1\displaystyle =\frac{1-2^n}{-1}

Multiplying top and bottom by -1

=2n11=2n1\displaystyle =\frac{2^n-1}{1}=2^n-1
Reply 21
Original post by ghostwalker
Sn=1(12n)1\displaystyle S_n=\frac{1(1-2^n)}{-1}

=12n1\displaystyle =\frac{1-2^n}{-1}

Multiplying top and bottom by -1

=2n11=2n1\displaystyle =\frac{2^n-1}{1}=2^n-1


How did I not see that :colondollar: Thanks anyway. Makes sense now :smile:

You've been a great help, so thank you very much!
Original post by mos182
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np

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