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    Maybe I am forgetting something basic but surely they could have just expanded x(1-x) = x - x2 and then integrated both sides to get:

    y = x2/2 - x3​/3 + c
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    (Original post by GPODT)
    Maybe I am forgetting something basic but surely they could have just expanded x(1-x) = x - x2 and then integrated both sides to get:

    y = x2/2 - x3​/3 + c
    It looks like there's a error on the paper; they change variables from y and x to x and t on the second line. I guess the real question had dx/dt on the LHS.
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    (Original post by atsruser)
    It looks like there's a error on the paper; they change variables from y and x to x and t on the second line. I guess the real question had dx/dt on the LHS.
    Ah I see thanks. My method is still ok right?
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    (Original post by GPODT)
    Ah I see thanks. My method is still ok right?
    I'd say so, but there is an error in the wording of the question, as if you had done it your way (which is the correct way if you're just looking at the question as it's given) then there would have been no need for the condition 0<x<1.
 
 
 
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