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    Using Bromoethane as an example.

    First step: CH3CH2Br + NH3 == CH3CH2NH2 + HBr

    WHy does it form HBr should it form jsut Br- not HBR?
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    (Original post by Tynos)
    Using Bromoethane as an example.

    First step: CH3CH2Br + NH3 == CH3CH2NH2 + HBr

    WHy does it form HBr should it form jsut Br- not HBR?
    Well it's just a matter of balancing the equation, if you look closely the NH3 when bonded to the chain becomes NH2 therefore a H+ is left aswell as the Br- hence HBr is made.

    Hope that clears things up

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    (Original post by Tynos)
    Using Bromoethane as an example.

    First step: CH3CH2Br + NH3 == CH3CH2NH2 + HBr

    WHy does it form HBr should it form jsut Br- not HBR?
    When NH3 attacks, it will form a 4th bond with the chain. Since Nitrogen only likes 3 bonds, this will cause it to have a positive charge. Since bromine will be negatively charged, it will take a hydrogen off the NH3 to form two, neutral, more stable molecules.

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    (Original post by Tynos)
    Using Bromoethane as an example.

    First step: CH3CH2Br + NH3 == CH3CH2NH2 + HBr

    WHy does it form HBr should it form jsut Br- not HBR?
    Yes it does eliminate Br- but this can then deprotonate the positively charged product. In reality HBr is so acidic and the Br- ion is so poorly basic, it is very unlikely the Br- would actually deprotonate the product. It would most likely be the solvent. If HBr was formed, it would just dissociate into Br- and [(solvent)H]+
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    Thanks alot guys.
 
 
 
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