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    Hello there,

    I've been doing this exam question from May 2009, and I'm stuck on part c of it! Looking at the mark scheme, shows me the same starting numbers, but with opposite signs, and I'm not sure how they've done it that way.

    Here is the question, my response and the mark scheme's response:

    Cheers in advance!

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    (Original post by KiddingMe)
    Hello there,

    I've been doing this exam question from May 2009, and I'm stuck on part c of it! Looking at the mark scheme, shows me the same starting numbers, but with opposite signs, and I'm not sure how they've done it that way.

    Here is the question, my response and the mark scheme's response:

    Cheers in advance!

    Name:  uploadfromtaptalk1364739618588.jpg
Views: 81
Size:  91.6 KB
    Name:  uploadfromtaptalk1364739637845.jpg
Views: 92
Size:  54.6 KB
    Name:  uploadfromtaptalk1364739629151.jpg
Views: 70
Size:  43.6 KB
    Well, it depends which way you're taking to be positive.
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    Because acceleration direction has changed, I'm doing left is positive and right is negative for part c
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    Any help further? Hehe
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    It is given that there is a thrust in the towbar, so you have chosen the wrong direction for T.

    If you think about it, it makes sense for there to be a thrust because whilst the car tries to slow down, the trailer will make it harder than it would be if there was no trailer.
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    Ah! I was still thinking it was tension.

    So, if we put a dashed line between the two objects, T would be in opposite direction? (So the direction of both T shown in my diagram drawn,would be 'flipped'?)

    Cheers : )
 
 
 
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