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# algebra check watch

1. Have i done these questions properly?
2. (Original post by CRPAl)

Have i done these questions properly?
The left most one and the one on the right are incorrect.
The middle one is correct
3. (Original post by CRPAl)

Have i done these questions properly?
First one you seem to have added the quadratic right at the end not subtracted it. Second one looks fine. Third one the 3 cancels in the powers, you don't cube the 3 in the denominator which it looks like you have done.
4. (Original post by metaltron)
First one you seem to have added the quadratic right at the end not subtracted it. Second one looks fine. Third one the 3 cancels in the powers, you don't cube the 3 in the denominator which it looks like you have done.
Would the answer to the first one be

4a^2 -13a +16?

I dont understand how to work out the third one
5. (Original post by CRPAl)
Would the answer to the first one be

4a^2 -13a +16?

I dont understand how to work out the third one
Again check your subtraction for the first one.
As for the third: When raising (Something)n to another power say m the new power = m*n
6. What answer are you getting for q1?

i have tried the third one again, so if you dont cube the 3 in the denominator:

$^{\(0.2a^{-2/3}\)^3\,=\,0.008a^{-2}\,=\,\frac{0.008}{a^2}\,=\,\frac{1}{125a^2}.}$
7. what answer are you getting for q1?

for q3 is it

1/125a^2
8. (Original post by CRPAl)
what answer are you getting for q1?

for q3 is it

1/125a^2
Yep its 1/ (125a^2)
9. (Original post by CRPAl)
what answer are you getting for q1?

for q3 is it

1/125a^2
Is that 1/(125a2) or 1/125 a2
You need to subtract ALL of the quadratic. You have everything correct apart from this.
10. 1/(125a^2) is what i think it is?

q1:
4a^2 -13a -16?
11. (Original post by CRPAl)
1/(125a^2) is what i think it is?

q1:
4a^2 -13a -16?
Correct for 1/(125a^2)
You still need to minus the 4a2

-4a^2 -13a -16?
13. (Original post by CRPAl)

-4a^2 -13a -16?
Seems legit
14. got there eventually thanks for your help guys

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