You are Here: Home

# Edexcel M2 concepts watch

Announcements
1. Does anyone know a site where I can get detailed information about the concepts in Mechanics 2 Edexcel, coz I find the revision guide and the book itself not elaborate enough and a bit untidy.

also:

work done = force x distance
work done = Kinetic Energy gained = 1/2mv^2-1/2mu^2

I was just wondering, is work done also:
work done = Kinetic Energy LOST = 1/2mu^2-1/2mv^2 ????

the book does not tell me if work done = kinetic energy lost, but I managed to do a question correctly in that book using that logic???!!!
2. Yes, work done is energy gained by the object being moved in the direction of the force, therefore due to the law of conservation of energy, work done must be the energy lost by the object providing the force in the direction of the motion.

Think of the energy of one object the potential to do work to another. So if one object is travelling at a speed, or at a high temperature, it can potentially do work on another object (although in the temperature example you wouldn't use the equation W=Fx because the object having the work done on it isn't strictly moving, however the energy is still being transferred).

Hope this helps. Bottom line, work it the transfer of energy, so if object A loses 10J in an inelastic collision with object B, the work done is 10J on B, therefore not only does B gain 10J, but A (as stated) loses 10J.
3. ahhh rite very well , that makes sense.

one more question, would u say overall KE lost = KE gained ?
4. Yep, because of the conservation of energy. Except that sometimes doesn't hold, because kinetic energy can be transferred into other forms. If you throw a ball upwards, in flight the KE of the ball decreases but it isn't hitting anything and giving anything it's loss in KE. So we say it gains GPE, gravitational potential energy. If you hit a mallet on a wall, the KE of the mallet isn't making the wall move that much, most of the energy goes to sound energy.

It is important in Physics to remember the equation (when something with KE is slowing down due to gravity, or something is speeding up under gravity): KE = GPE

Use each formula, and with enough values you can equate them. It helps to have that in the back of your head in mechanics questions.

Sorry I seem to have gone off on a tangent. Anyway I guess I answered your question somewhere back in the 1st paragraph.

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 16, 2004
Today on TSR

### Exam Jam 2018

Join thousands of students this half term

### Solo - A Star Wars Story

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE