In the second last line i don't fully understand what is harkening on the right hand side of the equality. On a very simplistic scale i see the dt and dt canceling out leaving me to integrate the vx ....
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Work energy theorem proof Watch
- Thread Starter
- 01-04-2013 12:23
- 01-04-2013 12:38
well if you differentiate (Vx)2/2 implicitly wrt t you get their expressionLast edited by the bear; 01-04-2013 at 12:39.