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OCR C4 (not mei) 18th June 2013 revision watch

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    I thought i'd start a thread for C4 OCR.





    Can anyone help me on this question:

    Expand binomially: 3/(2-x) + 3(1+x) +1/((1+x)^2)

    Well i know you have to convert it into (1-x) for the first one... but yeah...
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    (Original post by master y)
    I thought i'd start a thread for C4 OCR.





    Can anyone help me on this question:

    Expand binomially: 3/(2-x) + 3(1+x) +1/((1+x)^2)

    Well i know you have to convert it into (1-x) for the first one... but yeah...
    (2-x)^{-1}=2^{-1}(1-\frac{x}{2})^{-1}
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    Need 91 in this for an A*!
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    (Original post by erniiee)
    Need 91 in this for an A*!
    I need 93
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    I haven't even started revising
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    (Original post by master y)
    I need 93
    So do you think its true? That C4 is "easier" than C3? So far I much prefer C3 :lol:
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    (Original post by erniiee)
    So do you think its true? That C4 is "easier" than C3? So far I much prefer C3 :lol:
    I prefer C3 too, and i've heard C4 can be a right pain in the backside sometimes. Some of my friends sat the january exam, and came out with appalling results, and they are going to study maths/economics/engineering at oxbridge! I'm just a mere medic :afraid:
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    (Original post by master y)
    I prefer C3 too, and i've heard C4 can be a right pain in the backside sometimes. Some of my friends sat the january exam, and came out with appalling results, and they are going to study maths/economics/engineering at oxbridge! I'm just a mere medic :afraid:
    Ah not what I want to here :lol: Same here, I actually need 1 A* to meet my offer - wasn't originally expecting it from Maths but I think it's achievable!
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    Anyone got a good website for C4 Vectors? Any other decent resources for C4 are appreciated too
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    (Original post by Big Bad Boss)
    Anyone got a good website for C4 Vectors? Any other decent resources for C4 are appreciated too
    you may have already seen this but... http://www.examsolutions.net/maths-r.../C4/module.php
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    Does anyone know how to answer june 2008 Q4ii, and Q9iii please?

    http://www.ocr.org.uk/Images/62967-q...hematics-4.pdf

    thanks!
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    Haven't done C3 like most people have... But I'm doing this paper... Nervous as I need to maintain my A by receiving an average of high Bs in S1 (resitting), C3 & C4... Going to try and aim for the A* though!


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    (Original post by erniiee)
    Ah not what I want to here :lol: Same here, I actually need 1 A* to meet my offer - wasn't originally expecting it from Maths but I think it's achievable!
    I feel stupid for not doing this but how do you simplify,

    (20-5x)/(6x^2 - 24x)
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    (Original post by master y)
    I feel stupid for not doing this but how do you simplify,

    (20-5x)/(6x^2 - 24x)
    \frac{{20 - 5x}}{{6{x^2} - 24x}} = \frac{{ - 5(x - 4)}}{{6x(x - 4)}} =  - \frac{5}{{6x}}
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    (Original post by master y)
    I feel stupid for not doing this but how do you simplify,

    (20-5x)/(6x^2 - 24x)
    As above, thanks Quest!
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    (Original post by Quest)
    \frac{{20 - 5x}}{{6{x^2} - 24x}} = \frac{{ - 5(x - 4)}}{{6x(x - 4)}} =  - \frac{5}{{6x}}
    ahhh cheers dude!
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    sorry, i seem to be the only one who has questions haha!

    A curve has parametric equations x= 3cos^2(t), y = sin(2t)

    what is dy/dx? I cant differentiate dx/dt for some reason... well i wrote it in terms of sin(2t).. which is \frac{3}{2} - \frac{3}{2}\sin \22t... but it doesn't work! I'm supposed to get dy/dx = \frac{-2}{3}(cot(2t))


    (Original post by erniiee)
    .

    (Original post by Quest)
    .
    urgh, and how do you write in this latex thing quickly! I have to keep copying and pasting...
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    I'm doing C4 in June! It will be my last ever A-Level exam!!! (Hopefully!!)

    Personally I think it's quite a bit easier than C3! I got 79/100 in C3 and I need an A overall so get into Uni so anything over 80 in C4 will be good!

    So far:
    C1: 79, C2: 84, C3: 79, C4: ?, D1: 62 (Re-sitting), S1: ?
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    please someone help!! last question June 2009... HOW DO I DO THIS?? I found C, but do i need to find k?
    IM DESPERATE.
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    Does anyone know how to know the value of x for which the expansion is valid. Eg. (1+4x)^(3/2)
    I got x<= -1/4 but the mark scheme says (mod x )< 1/4.... HOW DOES THIS WORK? aaaaaaaarghhhhhhhh

    Thanks
 
 
 
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