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# C2 intergration edexcel watch

1. The diagram shows the finite region, R, bounded by the curve with equation y=x4+x), the line with equation y=12 and the y-axis. A) find coordinate A B) Find area R I have the coordinate as (2,12). I am having trouble with how to find the area. Any ideas?
2. (Original post by SophieL1996)
The diagram shows the finite region, R, bounded by the curve with equation y=x4+x), the line with equation y=12 and the y-axis. A) find coordinate A B) Find area R I have the coordinate as (2,12). I am having trouble with how to find the area. Any ideas?
Have you tried drawing a sketch?
3. (Original post by SophieL1996)
The diagram shows the finite region, R, bounded by the curve with equation y=x4+x), the line with equation y=12 and the y-axis. A) find coordinate A B) Find area R I have the coordinate as (2,12). I am having trouble with how to find the area. Any ideas?
What is the equation?
4. (Original post by Mr M)
What is the equation?
The equation for the curve is x(4+x) and for the line y=12
5. As it's quadratic there will be two answers, of which -6 is the other. You may find it easier with two coordinates. If I remember correctly, I think then you integrate and sub the x values in and subtract them from each other. Hope this helps, sorry my memory isn't too good but c2 was last year for me!

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6. (Original post by SophieL1996)
The equation for the curve is x(4+x) and for the line y=12
Ok that isn't what you put in your opening post!

Either change the subject and integrate or find and subtract your answer from the area of a rectangle.
7. Sorry that is no help to me... The parabola is positive with the horizontal line through it, the area is between A (point of intersection) the y axis and (0,0) What do I take away from what ?
8. (Original post by SophieL1996)
Sorry that is no help to me... The parabola is positive with the horizontal line through it, the area is between A (point of intersection) the y axis and (0,0) What do I take away from what ?
Who are you talking to?

Do you want to integrate with respect to x or to y. Either will work so you choose?

Edit: As this is C2 I would strongly recommend x.
9. (Original post by SophieL1996)
Sorry that is no help to me... The parabola is positive with the horizontal line through it, the area is between A (point of intersection) the y axis and (0,0) What do I take away from what ?
You can split it up into three rectangles, can you work it out from that?
10. (Original post by Jackabc)
You can split it up into three rectangles, can you work it out from that?
No, as I have never been taught that
11. (Original post by SophieL1996)
The diagram shows the finite region, R, bounded by the curve with equation y=x4+x), the line with equation y=12 and the y-axis. A) find coordinate A B) Find area R I have the coordinate as (2,12). I am having trouble with how to find the area. Any ideas?
could you attach the diagram, it will make it easier for me to help
12. (Original post by jadecross)
could you attach the diagram, it will make this easier to help
Yes I have been trying to but it won't upload
13. (Original post by SophieL1996)
No, as I have never been taught that
Me neither.

14. so intergrate between 0 and 2 for equation of curve and minus that from (2x12) ??
15. The shaded area in this diagram is

Can you see a rectangle that you could subtract this area from to find the area you are interested in?

16. (Original post by SophieL1996)
so intergrate between 0 and 2 for equation of curve and minus that from (2x12) ??
yes, it's as simple as that.
17. (Original post by jadecross)
yes, it's as simple as that.
ok thanks I shall have a go
18. Thanks I got the right answer of 40/3 thanks for all your help, especially the diagram (helped a lot!)
19. (Original post by Mr M)
Me neither.

(Original post by SophieL1996)
No, as I have never been taught that
Isn't it bounded by all these graphs twice? So if you worked out the area between -4 and 0, added it to the area under -6 and -4 and then added it to the area between 0 and 2. Or was you just on about one side?

Edit: lol you could still split it up into three rectangles though if you added the areas between 0 and 1, 1 and 1.5, and 1.5 and 2 but that might take a bit longer.
20. (Original post by Jackabc)
Isn't it bounded by all these graphs twice? So if you worked out the area between -4 and 0, added it to the area under -6 and -4 and then added it to the area between 0 and 2. Or was you just on about one side?

Edit: lol you could still split it up into three rectangles though if you added the areas between 0 and 1, 1 and 1.5, and 1.5 and 2 but that might take a bit longer.
You are making this WAY too difficult.

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