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    http://www.ocr.org.uk/Images/61388-q...hematics-2.pdf

    Question 4

    I got for the first part 22(4/5)

    What does this value represent I thought it represents the shaded region but it does not?
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    (Original post by IShouldBeRevising_)
    http://www.ocr.org.uk/Images/61388-q...hematics-2.pdf

    Question 4

    I got he first part the 22(4/5)

    What does this value represent I thought it represents the shaded region but it does not?
    You need the area under the line (the shape is a rectangle) minus the area under the curve
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    (Original post by IShouldBeRevising_)
    http://www.ocr.org.uk/Images/61388-q...hematics-2.pdf

    Question 4

    I got he first part the 22(4/5)

    What does this value represent I thought it represents the shaded region but it does not?
    Depends what you evaluated! integration usually gives you the area underneath a curve - typically between a curve and the x-axis. You may need to subtract the area you've found from the area of a rectangle to get the area of the shaded part.
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    (Original post by Indeterminate)
    You need the area under the line (the shape is a rectangle) minus the area under the curve

    (Original post by davros)
    Depends what you evaluated! integration usually gives you the area underneath a curve - typically between a curve and the x-axis. You may need to subtract the area you've found from the area of a rectangle to get the area of the shaded part.
    I did the exact thing in the mark scheme but did not subtract my answer form the area of the rectangle... I thought the work I did gave the area of the shaded region?

    Here is the mark scheme

    http://www.ocr.org.uk/Images/59336-m...me-january.pdf
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    (Original post by IShouldBeRevising_)
    http://www.ocr.org.uk/Images/61388-q...hematics-2.pdf

    Question 4

    I got for the first part 22(4/5)

    What does this value represent I thought it represents the shaded region but it does not?
    \int^2_-_2 x^4+3\ dx will give you the area underneath the curve.
    Then work out the Area of rectangle which is 4*19=76 and subtract this to get the required area.

    (sorry, limits were supposed to be -2 and 2)
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    (Original post by gaffer dean)
    \int^2_-_2 x^4+3\ dx will give you the area underneath the curve.
    Then work out the Area of rectangle which is 4*19=76 and subtract this to get the required area.
    Oh right yes thank you.. I thought integration gave you the area of the shaded region.
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    (Original post by IShouldBeRevising_)
    Oh right yes thank you.. I thought integration gave you the area of the shaded region.
    you're welcome, read section 11.2 in the book if you still don't understand.
    BTW, limits were supposed to be -2 and 2.
 
 
 
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