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    How would I answer this question?

    If Company A’s market cap is twice as large as Company B’s, and Company B’s market cap is three times as large as Company C’s, what is Company C’s market cap if all three market caps add up to £70m?
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    Here's a hint: Let Company C's market cap be "x"
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    (Original post by BananaPie)
    Here's a hint: Let Company C's market cap be "x"
    So would it be x + x^2 + x^3 = 70? As that's what I was thinking before
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    I wrote out the entire thing as equations.

    A = 2B
    B = 3C

    A+B+C = 70

    and then worked from there. Although I probably wouldn't take my advice, I haven't done maths in about 6 months...still my answer worked when you subbed it back in...give it a go
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    (Original post by shiv0203)
    So would it be x + x^2 + x^3 = 70? As that's what I was thinking before
    x^3 does not mean 3 \times x.
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    (Original post by shiv0203)
    So would it be x + x^2 + x^3 = 70? As that's what I was thinking before
    What you've written there is wrong. Read the question carefully and you'll get the answer. =]
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    You don't want x+2x+3x=70 either by the way. Read the question very carefully.
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    (Original post by BananaPie)
    What you've written there is wrong. Read the question carefully and you'll get the answer. =]
    Yeah I just realised I was over thinking it lol.
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    (Original post by Mr M)
    You don't want x+2x+3x=70 either by the way. Read the question very carefully.
    C should be 7 right?
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    (Original post by shiv0203)
    C should be 7 right?
    Yes but do you have an algebraic method now or did you just use trial and improvement?
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    (Original post by Mr M)
    Yes but do you have an algebraic method now or did you just use trial and improvement?
    Yes I have a method I just applied it wrong, I incorrectly assumed I should be making them exponentials. I don't think I could have used trial and improvement for a question like that...
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    (Original post by shiv0203)
    Yes I have a method I just applied it wrong, I incorrectly assumed I should be making them exponentials. I don't think I could have used trial and improvement for a question like that...
    Trial and improvement is actually easy.

    Pick a number for C (e.g. 10)

    B is three times as big as C (e.g. 30)

    A is twice as big as B (e.g. 60)

    But 10 + 30 + 60 = 100 and this is too big.

    Pick a smaller value for C and repeat.
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    (Original post by Mr M)
    Trial and improvement is actually easy.

    Pick a number for C (e.g. 10)

    B is three times as big as C (e.g. 30)

    A is twice as big as B (e.g. 60)

    But 10 + 30 + 60 = 100 and this is too big.

    Pick a smaller value for C and repeat.
    Lol that's rather tedious, who would spend time doing that? But yeah I guess you're right trial and error could work...
 
 
 
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