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# C4 edexcel differentiation watch

1. Hi, this question is from the Core 4 Edexcel textbook review exercise (question 38).

Find the coordinates of the minimum point on the curve with equation y=x2x

I worked out the x coordinate (-1/ln2) and this is correct according to the answers. Substituting this value into the original y equations, I assumed I could find the coordinate for y, but I seem to be unable to rearrange the equation to get an answer.

I'm stuck at y= (-1/ln2)(2^(-1/ln2))
2. (Original post by ameliagrrh)
Hi, this question is from the Core 4 Edexcel textbook review exercise (question 38).

Find the coordinates of the minimum point on the curve with equation y=x2x

I worked out the x coordinate (-1/ln2) and this is correct according to the answers. Substituting this value into the original y equations, I assumed I could find the coordinate for y, but I seem to be unable to rearrange the equation to get an answer.

I'm stuck at y= (-1/ln2)(2^(-1/ln2))
Rewriting may help.

EDIT: Having now attempted this question, I'd suggest that if you wanted to simplify further recall that:
3. I re-wrote it as y=-1/ln2 x 1/2^(ln2) but I can't seem to work it out, it's not clicking in my mind! :P
4. (Original post by ameliagrrh)
I re-wrote it as y=-1/ln2 x 1/2^(ln2) but I can't seem to work it out, it's not clicking in my mind! :P
in the denominator of the second fraction.
Welcome to TSR btw
5. I GOT IT. Oh I love it when things click
Thanks so much for your help!
6. (Original post by ameliagrrh)
I GOT IT. Oh I love it when things click
Thanks so much for your help!
No Prob

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