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# C4 Differentiation Question watch

1. Given that y=2^x and using the result 2^x = e^(xln2), or otherwise,

show that dy/dx = 2^x ln2

Then find the gradient of the curve with equation y = 2^(x^2) at point (2,16)

Cheers
2. Have you tried differentiating y=e^(xln2) ?

What have you done so far?

3. Does this help?
4. y=2^x
=e^(xln(2))
=e^(ln(2^x))

Use y=e^xln(2)

So,

dy/dx=ln(2)*e^(xln(2))
=ln(2)*e^ln(2^x)
=ln(2)*(2^x)
=(2^x)*ln(2)
5. (Original post by paper-may)
...
Are you aware of the forum guidelines that ask us not to post full solutions
6. (Original post by TenOfThem)
Are you aware of the forum guidelines that ask us not to post full solutions
Clearly not.
7. (Original post by paper-may)
Clearly not.
Front page of maths

8. (Original post by TenOfThem)
Front page of maths

Ain't nobody got time for that.
9. (Original post by paper-may)
Ain't nobody got time for that.
whatever

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