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# Cot x watch

1. Hi there!

Just a question regarding cot x. I was tackling a question on integration for C4 and came across needing to substitute pi/2 into 1/cotx. I didn't think this was possible as tan(pi/2) is undefined, so I thought no solution.

However, the mark scheme has that pi/2 into 1/cotx gives 0. Is this because 1/undefined = so tiny it is zero? Or is the mark scheme wrong?

Thanks very much for any help
2. (Original post by Mynameisnotearl)
Hi there!

Just a question regarding cot x. I was tackling a question on integration for C4 and came across needing to substitute pi/2 into 1/cotx. I didn't think this was possible as tan(pi/2) is undefined, so I thought no solution.

However, the mark scheme has that pi/2 into 1/cotx gives 0. Is this because 1/undefined = so tiny it is zero? Or is the mark scheme wrong?

Thanks very much for any help

3. (Original post by Mynameisnotearl)
Hi there!

Just a question regarding cot x. I was tackling a question on integration for C4 and came across needing to substitute pi/2 into 1/cotx. I didn't think this was possible as tan(pi/2) is undefined, so I thought no solution.

However, the mark scheme has that pi/2 into 1/cotx gives 0. Is this because 1/undefined = so tiny it is zero? Or is the mark scheme wrong?

Thanks very much for any help
Well and at you end up with a 0 on the denominator.

at you do not end up with a 0 on the denominator.

Also, if a function at some then at
4. ^^ They need to put some analysis in the A-level syllabus.
5. Thanks everyone

Seems obvious and simple now - kicking myself for spending 20 mins stuck on this.

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