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    • Thread Starter
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    10i)

    http://www.ocr.org.uk/Images/59552-q...hematics-4.pdf


    For k I got .07438118316

    The answer for k is .07438118377

    I can't figure out where I have gone wrong...

    I got K = Ln [ 3^(-1/3) * 5^(1/3) ] - 0.2310490602
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    (Original post by IShouldBeRevising_)
    10i)

    http://www.ocr.org.uk/Images/59552-q...hematics-4.pdf


    For k I got .07438118316

    The answer for k is .07438118377

    I can't figure out where I have gone wrong...

    I got K = Ln [ 3^(-1/3) * 5^(1/3) ] - 0.2310490602
    Assuming you used the partial fractions form in (i) to do (ii), you may have made an error integrating or using the initial conditions.

    Post working
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    (Original post by IShouldBeRevising_)
    10i)

    http://www.ocr.org.uk/Images/59552-q...hematics-4.pdf


    For k I got .07438118316

    The answer for k is .07438118377

    I can't figure out where I have gone wrong...

    I got K = Ln [ 3^(-1/3) * 5^(1/3) ] - 0.2310490602
    Where have you got all those horrible decimals from?

    The answer is given in an exact form, so keep everything expressed as ln(something) until you get to the very end and then everything drops out nicely!
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    (Original post by davros)
    Where have you got all those horrible decimals from?

    The answer is given in an exact form, so keep everything expressed as ln(something) until you get to the very end and then everything drops out nicely!
    Yeah I did again but this time kept everything in exact form and got the correct answer, thanks.
 
 
 
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