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# Int 2 Maths help Watch

1. Hey, I need help with one queestion

If sinx = 4/5 and cosx= 3/5 calculate the value of tanx.

That's what I've done:
tanx = sinx/cosx
= (4/5) ÷ (3/5)
= (4/5) * (5/3)
= 20/15
= 5/3

But the marking instructions say that the answer is 4/3.
What am I doing wrong?

Thanks
2. (Original post by Nessie162)
Hey, I need help with one queestion

If sinx = 4/5 and cosx= 3/5 calculate the value of tanx.

That's what I've done:
tanx = sinx/cosx
= (4/5) ÷ (3/5)
= (4/5) * (5/3)
= 20/15
= 5/3

But the marking instructions say that the answer is 4/3.
What am I doing wrong?

Thanks
20/15 = 4/3, not 5/3...

(4/5) / (3/5)
= (4/5) x (5/3)
= (20/15)
= (4/3)
3. Oh Jesus, what a fail, I can't ever divide properly.

Thanks btw
4. An easier method would be to draw a triangle, and make the hypotenuse 5 then go from there
5. (Original post by CSM1996)
An easier method would be to draw a triangle, and make the hypotenuse 5 then go from there
Damn boy, that's some ancient Greek thinking right there.
6. (Original post by Hype en Ecosse)
Damn boy, that's some ancient Greek thinking right there.
Thank you kind sir :]

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