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# Another physics question. Components. watch

1. sorry, I'm really bad at physics -_-

idk if what i wrote for the first bit is correct?

im suppose to have gotten to question 50 by tomorrow
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2. oh and this
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3. (Original post by hibaj)
sorry, I'm really bad at physics -_-

idk if what i wrote for the first bit is correct?

im suppose to have gotten to question 50 by tomorrow
Let me get my ant glasses

The weight has no horizontal component so doesn't balance the force of the rope and it follows that the rope has no vertical component so doesn't balance the weight of the ball
4. For the first part, you need to be considering the forces that are working in the horizontal direction, then in the vertical direction for the second. The ball's weight does not balance the 1200N force because W has no horizontal component (whereas the 1200N force is only horizontal). Similarly, the 1200N doesn't balance the weight because it has no vertical component.

For part b), you need to consider all of the horizontal forces working on the ball, then all of the vertical. This will give you an equation in terms of tension T for each.
5. (Original post by hibaj)
sorry, I'm really bad at physics -_-

idk if what i wrote for the first bit is correct?

im suppose to have gotten to question 50 by tomorrow
As above, the weight has no horizontal component.
Spoiler:
Show
The horizontal component of the tension in the rope

Hopefully you can then deduce the answer to the second part.

As for part b)
Hints:

• The weight of an object is the mass() * acceleration due to gravity (in )
• Forces that don't act solely horizontally and vertically can be resolved using trigonometry
• The angles can be found using Forces in trigonometry

Hope this helps!
Quote me if you need further assistance, or feel free to direct message me
6. (Original post by Felix Felicis)
Let me get my ant glasses

The weight has no horizontal component so doesn't balance the force of the rope and it follows that the rope has no vertical component so doesn't balance the weight of the ball
Thank you!
Sorry, it sounded like I only needed help with that question, but it's the whole thing so if it's not a problem could you tell me if the following is correct:

what I got for the question after that is 2500N and the one after I got 1200N is that correct?

and then for iii would I used pythag theorem?

PS why did you need your ant glasses? xD is the photo small?

Thank youuuuu
7. (Original post by hibaj)
Thank you!
Sorry, it sounded like I only needed help with that question, but it's the whole thing so if it's not a problem could you tell me if the following is correct:

what I got for the question after that is 2500N and the one after I got 1200N is that correct?

and then for iii would I used pythag theorem?

PS why did you need your ant glasses? xD is the photo small?

Thank youuuuu
If you treat then yes, the vertical component is 2500 N and the horizontal is 1200 N . And you just do pythagoras for the magnitude of the tension in the rope.

NOOOOO, it's not small at all

No problem sweet cheeks
8. (Original post by hibaj)
Thank you!
Sorry, it sounded like I only needed help with that question, but it's the whole thing so if it's not a problem could you tell me if the following is correct:

what I got for the question after that is 2500N and the one after I got 1200N is that correct?

and then for iii would I used pythag theorem?

PS why did you need your ant glasses? xD is the photo small?

Thank youuuuu
Yep, that all seems to check out as far as I can tell. You add the components in iii using Pythagoras, then you find the angle it makes using trigonomnomnomnometry.
9. (Original post by wrexhamfc)
For the first part, you need to be considering the forces that are working in the horizontal direction, then in the vertical direction for the second. The ball's weight does not balance the 1200N force because W has no horizontal component (whereas the 1200N force is only horizontal). Similarly, the 1200N doesn't balance the weight because it has no vertical component.

For part b), you need to consider all of the horizontal forces working on the ball, then all of the vertical. This will give you an equation in terms of tension T for each.

Thanks! Not sure I understood what you meant for part B.

(Original post by chapmouse)
As above, the weight has no horizontal component.
Spoiler:
Show
The horizontal component of the tension in the rope

Hopefully you can then deduce the answer to the second part.

As for part b)
Hints:

• The weight of an object is the mass() * acceleration due to gravity (in )
• Forces that don't act solely horizontally and vertically can be resolved using trigonometry
• The angles can be found using Forces in trigonometry

Hope this helps!
Quote me if you need further assistance, or feel free to direct message me
Thank you! I think that is what I did.

Thanks agaiin
10. (Original post by Felix Felicis)
If you treat then yes, the vertical component is 2500 N and the horizontal is 1200 N . And you just do pythagoras for the magnitude of the tension in the rope.

NOOOOO, it's not small at all

No problem sweet cheeks
I treated it as 9.81 N/kg but then I wrote it to 2sf x)

Thanks sooo much!

You guys are awesome!

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