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    A few questions I got stuck on, a brief explanation on each would be great, the answers are
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    B B A B B D
    thanks.
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    (Original post by Lay-Z)
    A few questions I got stuck on, a brief explanation on each would be great, the answers are
    Spoiler:
    Show
    B B A B B D
    thanks.
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Views: 71
Size:  116.6 KBName:  12031213.png
Views: 63
Size:  40.4 KBName:  38300660.png
Views: 64
Size:  62.6 KBName:  14609352.png
Views: 54
Size:  24.4 KBName:  75011768.png
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    for no.13 i believe (i may be wrong, I havent actually done this topic yet):
    Firstly the additional charge has no difference as the charges are now +2Q to -Q instead of +Q to -2Q, so the difference is the same (and still equally spaced either side of 0)
    I also think that force decreases as the square of the distance? In which case the answer is A - an attractive force of F/4
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    2.
    Use the density and volume discharge per sec to work out the mass discharge per sec.

    Use the volume discharge per sec and the cross sectional area to work out the velocity.
    Use the mass per second and velocity to calculate the momentum.
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    (Original post by Joinedup)
    2.
    Use the density and volume discharge per sec to work out the mass discharge per sec.

    Use the volume discharge per sec and the cross sectional area to work out the velocity.
    Use the mass per second and velocity to calculate the momentum.
    1000x2x10-4=0.2kgs^-1

    how can you work out velocity from volume discharge rate? Dont think it is in my syllabus?
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    (Original post by Lay-Z)
    1000x2x10-4=0.2kgs^-1

    how can you work out velocity from volume discharge rate? Dont think it is in my syllabus?
    think about it as calculating the length of one seconds worth of water.

    If you had a cylinder of ice of constant known cross section and volume you'd be able to work out the length of it.
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    (Original post by Joinedup)
    think about it as calculating the length of one seconds worth of water.

    If you had a cylinder of ice of constant known cross section and volume you'd be able to work out the length of it.
    I got it now thanks, the length travelled in 1 second = velocity
 
 
 
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