The Student Room Group
<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>
<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>
<a https://www.thestudentroom.co.uk/showthread.php?t=7467335'> Year 12s: what will be the first way you research your future options? >>

first and second derivative

Can anyone provide me "steps" as to how this is to be worked out? Thanks

f(x) = (1-q1-q2)*q1-c*q1

The first derivative, with respect to q1 of this function is:

1-2q1-q2-c

And the second is -2

The stationary point is at q1 = 1-q2-c/2
Reply 1
Avatar for joostan
joostan
13
Original post by oj234
Can anyone provide me "steps" as to how this is to be worked out? Thanks

f(x) = (1-q1-q2)*q1-c*q1

The first derivative, with respect to q1 of this function is:

1-2q1-q2-c

And the second is -2

The stationary point is at q1 = 1-q2-c/2

The easiest way to see this is to expand the bracket then differentiate with respect to q1 in the normal manner.
Reply 2
Avatar for oj234
oj234
OP
1
Original post by joostan
The easiest way to see this is to expand the bracket then differentiate with respect to q1 in the normal manner.


got it
(edited 11 years ago)
Original post by oj234
how do i expand this?


You know how to expand brackets, right?

Also, it's f(q1)f(q_1) and not f(x)f(x)

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you