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    Cu+ + e- ß>Cu 0.52v
    Cu2+ + e- ß>Cu+ +0.15v

    Use the data to show this reaction below is likely tooccur
    2Cu+ àCu2+ + Cu

    More positive E value means species is more likely to bereduced. Cu+ is more likely to be reduced (0.52) than Cu2+ (0.15), this occursin the reaction above, (Cu+ is reduced toCu), so this reaction is more likelyto move forward/occur.
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    (Original post by ILoveUSA)
    Cu+ + e- ß>Cu 0.52v
    Cu2+ + e- ß>Cu+ +0.15v

    Use the data to show this reaction below is likely tooccur
    2Cu+ àCu2+ + Cu

    More positive E value means species is more likely to bereduced. Cu+ is more likely to be reduced (0.52) than Cu2+ (0.15), this occursin the reaction above, (Cu+ is reduced toCu), so this reaction is more likelyto move forward/occur.
    E = E(red) - E(ox)

    Cu+ being reduced is +0.52V
    Cu+ being oxidised is +0.15

    E(red) - E(ox) = +0.37V

    positive and greater than 0.3V so likely to go to completion.
 
 
 
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