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    Hi,
    Can someone please help me on this question for Chem

    For (a), I got 3.51785 x 10^-3mol
    I'm stuck on the (b) part of the question :P

    Help?


    Thank you in advance (:
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    Work backwards.

    for convenience sake, i will double the first equation,

    2Fe3+ + 2I- ---> I2 + 2Fe2+

    I2 + 2S2O32- ---> 2I- + S4O62-

    then ratio of Fe3+ : I2 : S2O3 would be 2 : 1 : 2

    from part (i), mol of Na2S2O3 = something

    then mol of Fe(III) ions reacted (i.e. 25 cm cube) = ?
 
 
 
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