Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter

    Could you please help me on this question or answer it please?

    A van of mass 1200kg moves along a horizontal straight road. At time t seconds, the resultant force on it has magnitude 60000/(t+5)^2 and acts in the direction of motion of the van. When t=0, the van is at rest. the speed of the van approaches a limiting value Vms^-1.


    A) the value of V,

    B) The distance moved by the van in the first 4 seconds of its motion.

    Thank you!
    • PS Helper
    • Study Helper

    PS Helper
    Study Helper
    For part A: you have \int_{0}^{\infty}F dt = m V = \int_{0}^{\infty}\frac{60000}{(t  +5)^2} dt; you can evaluate the integral to get a value for V. My answer (jotted on an envelope so may be wrong) is in the spoiler:

    The distance moved by the van is fairly easy now because you have an expression for its instantaneous velocity at time t':
    \int_{0}^{t'}F dt = m v(t'), so you can integrate both sides again to get an expression for x(t').
Do you agree with the PM's proposal to cut tuition fees for some courses?
Useful resources

Make your revision easier


Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here


How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.