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    Could you please help me on this question or answer it please?


    A van of mass 1200kg moves along a horizontal straight road. At time t seconds, the resultant force on it has magnitude 60000/(t+5)^2 and acts in the direction of motion of the van. When t=0, the van is at rest. the speed of the van approaches a limiting value Vms^-1.

    Find:


    A) the value of V,


    B) The distance moved by the van in the first 4 seconds of its motion.


    Thank you!
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    For part A: you have \int_{0}^{\infty}F dt = m V = \int_{0}^{\infty}\frac{60000}{(t  +5)^2} dt; you can evaluate the integral to get a value for V. My answer (jotted on an envelope so may be wrong) is in the spoiler:
    Spoiler:
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    V=10m/s

    The distance moved by the van is fairly easy now because you have an expression for its instantaneous velocity at time t':
    \int_{0}^{t'}F dt = m v(t'), so you can integrate both sides again to get an expression for x(t').
 
 
 
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