# Core 2 AQA - monday 22 may 06Watch

#1
how did the test go??

was a retake for me and i found it to be a very onice paper hopefully i get a decent mark on it, lol
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12 years ago
#2

I found this harder than previous years!
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12 years ago
#3
I think it was ok.. there were a couple of questions that threw me at first but the more I looked at them the more they made sense.

I answered all the questions and couldn't see any that were blatantly wrong or that I just couldn't work out.

For the last question, did you get tan theta = 3 and then get the same answers that you'd got before for tan 1/2 theta = 3? And in that question did you just get 2 answers?

Ooh AND for the transformation from y = tanx to y = tan1/2x was it stretch by scale factor 2 in the direction of the x axis? I'm useless with transformations and just hoped for the best with that question..
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12 years ago
#4
(Original post by squirly)
I think it was ok.. there were a couple of questions that threw me at first but the more I looked at them the more they made sense.

I answered all the questions and couldn't see any that were blatantly wrong or that I just couldn't work out.

For the last question, did you get tan theta = 3 and then get the same answers that you'd got before for tan 1/2 theta = 3? And in that question did you just get 2 answers?

Ooh AND for the transformation from y = tanx to y = tan1/2x was it stretch by scale factor 2 in the direction of the x axis? I'm useless with transformations and just hoped for the best with that question..
Yea, that's what i got.

Although i didn't knwo what to do for the binomial expansion part when it said 'find the coefficient of x in (2+x)^9

:|
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12 years ago
#5
for the binomial expansion, all you had to do was start working it out (9C0 (2)^9 + 9C1 (2)^8(x) + .....) so then the coefficient would be 9 x 2^8....well thats what i did lol

The last question was quite confusing though....i worked out that cos(theta)=0 therefore theta=invcos0 = 90 degrees
and the other one was sin(theta)=3cos(theta)
= sin(theta) = 3
cos(theta)
which i fink came out as 71 degrees...i didn't know what to do from there
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12 years ago
#6
For the first binomial expansion I got:
9C1 x 2^8 = 2304

And for the 2nd part of it I got:
13C1 x 1^4 x 2^8 = 3328
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12 years ago
#7
aaah i see.
i've never done a question/been taught about that.
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12 years ago
#8
The only questions that tripped me up a bit was the "find the value of n" which i worked out to be 50
and the two binomial ones where you had to find the coefficients.
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#9
(Original post by squirly)
For the first binomial expansion I got:
9C1 x 2^8 = 2304

And for the 2nd part of it I got:
13C1 x 1^4 x 2^8 = 3328
i didnt get that, wasnt it askin for the x coeff of (1-root2)^4 ?

how did u do the third part? just add the two coeff?
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12 years ago
#10
found it easy as, I'm pretty sure that I got the A and about 90% ish
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12 years ago
#11
You used them 2 equations from previous, they both relate to the question.

My mate got 2300, he said he added them together or some ****.
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12 years ago
#12
for the coefficent's i got -8, 2304 and then (-8)*(2304) ...
I got stuck on the last question, where i got 4 answers for the tan(1/2x) = 3: 2.498, and then add pi to answers, and for the last bit, i mucked up ! i didnt realise it would re-arrange to get the same equation as before!! But I found the paper fairly easy, but the hard bits were hard!!
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12 years ago
#13
(Original post by stratomaster)
The only questions that tripped me up a bit was the "find the value of n" which i worked out to be 50
and the two binomial ones where you had to find the coefficients.
yeah to answer that question, i use the quadratic formul and i managed to find out that n=50 or n=49.333
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12 years ago
#14
wasnt it n=50 and n= -49.33333?
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12 years ago
#15
(Original post by Singh_87)
wasnt it n=50 and n= -49.33333?
Yes, and because it was the sum of a number of terms, it is impossible for n to be a negative number, so n had to be 50.
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12 years ago
#16
ye...thats what i thought.. ...what about the last question, tan(1/2x)=3...what answers did you get, and how many were there that were valid between 0 and 4pi....?
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12 years ago
#17

2.50 and 8.78

I hope dats right.
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12 years ago
#18
I think I got them.. I know I got 1.25 as the first value for tan1/2x so I must have gotten 2.50 for the tanx one.
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12 years ago
#19
Is that you on your prick, cos you look like a ****ing geek ^^.
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12 years ago
#20
Wow, either I've done a completely different C2 exam to you or I've mucked up all the questions in a huge way... but those were not my answers!
Is this the exam which had the question on finding the region R on the last page?
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