C1 & C2 AqaWatch

12 years ago
#41
Since it seems like the question of the paper, I got n=50.
I was pleased with this exam, for me it was a resit after having completed C3/C4/FP1/FP2 and it looks like this paper contained an awful lot of calculus and trig, which are completely bashed around in the rest of the single and further courses.

I'm pleased with how it went - better than June 2005 which had waaay too much sequences and series stuff which this didn't!
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12 years ago
#42
anyway what coefficient did we have to find of the second bracket, was it 8?
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12 years ago
#43
what did every1 get for the chord and centre of circle question, i dropped a line from the centre through the chord, thus disecting it at the midpoint and you could do pythagoras, got root 2 as the answer i think

i dont think i got the coeffient question right, i got 4800x exactly, no1 else i know has this...although i got the first part of this question right i think
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12 years ago
#44
yes i also got root 2 as the answer, there was no way you could find the midpoint as you didn't have any coordinates for the chord only the length, but i used pythagoras to find the answer, anyway how did you do the equal roots question, bcos there was two squared terms of x and k??????
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12 years ago
#45
(Original post by kazoo)
squirly, where an earth did you get 20 from?
No, sorry, that's not a 20 that's my lack of being able to put theta. I meant 3 cos squared theta

And that chord one, if you drew it out, gave you a right angled triangle with sides 8 (the chord), root 18 and root 18 (the radii). To get the perpendicular distance between the chord and the centre, you draw a line, which splits this triangle (created by the chord and the radii) in half. You then have two triangles, each with sides 4, root 18 and x (the distance you need to find).

Using Pythagoras you get x^2 = 18 - 16 therefore x = root 2 (I HOPE!!!!)
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12 years ago
#46
dunno i just did (3root2)^2 = 4^2 + b^2

you cant have a negative root for a length if thats what you mean
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12 years ago
#47
(Original post by Scott Storch)
No you silly sausage, was on the back of paper 1.
I don't remember at all! What was it like? I know I did it but I don't remember it having a k at all
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12 years ago
#48
i got root 2 aswell, seems to be the general concensus
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12 years ago
#49
by the way i got 2288x as a coefficientfor the last binomial question.
can someone PLEASE tell me how they did last question on c1, i managed to show it, but to do equal roots where b2-4ac = 0, how could you when there were two squared terms with NO common factor, which doesn't make it a quadratic!!!!!!!!!!!!!!!!!!!
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12 years ago
#50
on the k one on the back of core one did anyone get an answer, lol i did and someone i know got the same

k= 4 or k= -2 is what i got
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12 years ago
#51
the last question on core one, after much work i got down to

4k^2 - 8k - 32

divide by 4 equals

k^2 - 2k -8

factorise

(k-4)(k+2)

k=4 and k=-2
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12 years ago
#52
and for the binomial one i got 4114x, cant really remember how but i did
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12 years ago
#53
I Got Up To That Stage But You Could Not Have Those 2 As Factors As Both Brackets Were Positive, But It Did Involve A 4 An 2, Well Hopefully I Got Atleast A Mark
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12 years ago
#54
OHHHH I remember now. I got k<-2 or k>4.
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12 years ago
#55
i think i got that aswell....it was annoying though becuase ther were4 things to choose from to be a, b, c so i just gessed in the end, looks like i got it right though!
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12 years ago
#56
there wasnt anything on inequalities on the paper was there? or did i just miss something?
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12 years ago
#57
I thought the last one on C1 was an inequalities one because it asked for equal roots. Isn't that where b^2 - 4ac > 0? I wasnt 100% sure on that one, but I thought it was because it said the range of values for k I think.
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12 years ago
#58
what did every1 get as the factors of the polynomial, i think i got (x-3)(x-1)(x) or some variation of the signs, but it was those intergers
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12 years ago
#59
there were no inequalities so how can the question involve inequalities?
what i want to know is how did you manage to put both x and k into an squared term, as they did not have a common factor, pls can someone answer
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12 years ago
#60
equal roots is where it is = 0
no roots b2-4ac< 0
2 roots b2-4ac > 0
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