# C1 & C2 AqaWatch

12 years ago
#61
kazoo what was the question exactly? I really don't remember it. If you remind me of it I can tell you how I did it.
0

12 years ago
#62
(Original post by dups45)
equal roots is where it is = 0
no roots b2-4ac< 0
2 roots b2-4ac > 0
oh *******s. I sat there debating whether one root or two roots meant equal roots and went for 2 because it was an even number
0
12 years ago
#63
erm... ok you must be talking about c1 and c2 so im going...

and -1732 was the right answer in the c2 binomial question ;-)
0
12 years ago
#64
how? explain?
0
12 years ago
#65
the question had a k's and x's in with coefficients, but it was not in a quadratic form, as you had to take out k and x as a common facotr, which was not possible, does anyone else know the question im on about?
also how do u know -1732 is right, how did you get it, it is not possible as i have worked it out using my knowledge and the book
0
12 years ago
#66
(Original post by dups45)
what did every1 get as the factors of the polynomial, i think i got (x-3)(x-1)(x) or some variation of the signs, but it was those intergers
yey i got that

for the last question on C2 about tan1/2x=3 what did you put as what happened to the graph and what were the values you got as i think i got it very wrong
0
12 years ago
#67
I didn't get -1732. How did you get it and how are you sure it's right?
0
12 years ago
#68
(Original post by squirly)
I got:

logay + loga5 = 7
loga5y = 7
5y = a^7
y = a^7
........5
God damn, I forgot to divide by 5.

(Original post by Shehna)
I have no idea....I just want to forget about it. Tha January paper was so easy compared to this one.
It was so much more easier, I got around 85% in a mock and I think I'll be pushing 60/70 for this one.

Could have gone worse though.
0
12 years ago
#69
This is what I got for the last question:

cos0(sin0 - 3cos0) = 0 (i can't to theta either)

Therefore.....
cos0 = 0 or
sin0 - 3cos0 = 0

cos0=0
0 = cos-1(0)

sin0 - 3cos0 = 0
sin0 = 3cos0
sin0/cos0 = 3
tan0 = 3
0 = tan-1(3)

Am I the only one who didn't multiply out the brackets?

For the binomial one, I got -1732 or thereabouts
0
12 years ago
#70
what did people get for the tan part of the last question and the values from 0 to 4pie
0
12 years ago
#71
I got 3 values i think.. 2.15, 8 point something and 1 point something
0
12 years ago
#72
its -1732 because you worked out the factors for x in both - so the factor for x would be the sum of those two... it was -4096 and 2304... i cant remember completely though - i did a similar question at the weekend ;-)
0
12 years ago
#73
This is what I got for the last question:

cos0(sin0 - 3cos0) = 0 (i can't to theta either)

Therefore.....
cos0 = 0 or
sin0 - 3cos0 = 0

cos0=0
0 = cos-1(0)

sin0 - 3cos0 = 0
sin0 = 3cos0
sin0/cos0 = 3
tan0 = 3
0 = tan-1(3)

Am I the only one who didn't multiply out the brackets?

i did the same
0
12 years ago
#74
i got 2 values which were 1.something and 2 which were 4.something - it wouldnt be 8.something because the first part said tan(1/2x)=3, and the 2nd part said tan(x)=3
0
12 years ago
#75
I didn't do tan0 I used the sin0+cos0=1 to get a quadratic.. might not be completely right but im not really arsed lol
0
12 years ago
#76
well i got 2 something and 3 somethingso i am done but oh well i will just resit in jan
0
12 years ago
#77
still cant see how anyone got a - for the binomial question
0
12 years ago
#78
- cos of the -x in the first expansion
n -1732 is definitely right i checked it over with a friend a couple times
i got the two correct numbers but added instead of subtracting givin me 6400
hopeful for 2 outta 3 marks
0
12 years ago
#79
well, i have worked out the answer now and that is incorrect, you try work it out

was their translation of 0 and -27

also how to do last q on c1?, when there are 2 coefficients of x^2!!!!!!!!
0
12 years ago
#80
i stuffed up i found C1 alright but C2 was too hard! Definately lost a lot of marks in C2
0
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