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    Simplify: 5sin23theta +5cos23theta and (1+sinx)2 + (1-sinx)2 + 2cos2x can you please show me step by step...
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    (Original post by SophieL1996)
    Simplify: 5sin23theta +5cos23theta (1+sinx)2 + (1-sinx)2 + 2cos2x can you please show me step by step...
    What have you done?
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    (Original post by BabyMaths)
    What have you done?
    I cant do these ones
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    (Original post by SophieL1996)
    I cant do these ones
    You can do something with it surely.

    It doesn't matter if what you try first isn't the best idea. You just have to try!

    Edit: neg. lol.

    My advice was well meant and it is good advice.
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    (Original post by BabyMaths)
    You can do something with it surely.

    It doesn't matter if what you try first isn't the best idea. You just have to try!
    Yes I have tried... but I cannot get the right answer, I just need someone to do the steps for me so I can have a go at some other ones...
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    (Original post by SophieL1996)
    Simplify: 5sin23theta +5cos23theta (1+sinx)2 + (1-sinx)2 + 2cos2x can you please show me step by step...

    (Original post by SophieL1996)
    I cant do these ones
    Have you even simplified the part I have highlighted
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    (Original post by SophieL1996)
    I just need someone to do the steps for me so I can have a go at some other ones...
    If this were the case then you would be able to use the examples in your text or those that your teacher has given you
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    (Original post by SophieL1996)
    Yes I have tried... but I cannot get the right answer, I just need someone to do the steps for me so I can have a go at some other ones...
    Expand the two brackets, that should cancel some terms, then you need to use the rule sin^2\theta + cos^2\theta=1 (same can apply for x terms btw, not just theta)
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    (Original post by TenOfThem)
    If this were the case then you would be able to use the examples in your text or those that your teacher has given you
    My teacher didb't really go into any of it and the examples are a lot easier than these questions, so I am stuck. Any help would be appreciated.
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    (Original post by SophieL1996)
    Yes I have tried... but I cannot get the right answer, I just need someone to do the steps for me so I can have a go at some other ones...
    I have just realised these are 2 different questions

    The one that I highlighted is very straightforward ... what have you tried

    Then 5\sin ^2A = 5\cos ^2A = 5(\sin ^2A + \cos ^2A)

    And you should certainly know what \sin ^2A + \cos ^2A =
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    (Original post by Robbie242)
    Expand the two brackets, that should cancel some terms, then you need to use the rule sin^2\theta + cos^2\theta=1
    So far I have got 2 + 2sinx2+2cos2x
    where do I go from there?
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    (Original post by SophieL1996)
    My teacher didb't really go into any of it and the examples are a lot easier than these questions, so I am stuck. Any help would be appreciated.
    Since these only require you to

    Multiply Brackets
    Know that \sin ^2A + \cos ^2A = 1
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    (Original post by SophieL1996)
    So far I have got 2 + 2sinx2+2cos2x
    where do I go from there?
    Are you saying that you do not know what \sin ^2A + \cos ^2A =
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    (Original post by SophieL1996)
    So far I have got 2 + 2sinx2+2cos2x
    where do I go from there?
    Take out a factor of 2 and follow a similar process to what TenOfThem has done hint: sin^2\theta + cos^2\theta=1
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    (Original post by TenOfThem)
    I have just realised these are 2 different questions

    The one that I highlighted is very straightforward ... what have you tried

    Then 5\sin ^2A = 5\cos ^2A = 5(\sin ^2A + \cos ^2A)

    And you should certainly know what \sin ^2A + \cos ^2A =
    So far I have got 2 + 2sinx2+2cos2x
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    (Original post by SophieL1996)
    Simplify: 5sin23theta +5cos23theta and (1+sinx)2 + (1-sinx)2 + 2cos2x can you please show me step by step...
    Why didn't you the and in in the first place?
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    (Original post by SophieL1996)
    So far I have got 2 + 2sinx2+2cos2x
    And, as I have said

    Do you know what \sin ^2x + \cos ^2x =
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    (Original post by TenOfThem)
    Are you saying that you do not know what \sin ^2A + \cos ^2A =
    it equals 1...
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    (Original post by SophieL1996)
    it equals 1...
    So what would 2 times it equal to?
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    (Original post by Robbie242)
    So what would 2 times it equal to?
    2
 
 
 
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