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general solutions

find the general solution of dy/dx = e^(x-y) by seperating the variables.

the answer is y=ln (e^x+c)

but I'm not sure how to split the x and y

I got 1/e^(x-y) dy = dx to integrate?
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joostan
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Original post by 0utdoorz
find the general solution of dy/dx = e^(x-y) by seperating the variables.

the answer is y=ln (e^x+c)

but I'm not sure how to split the x and y

I got 1/e^(x-y) dy = dx to integrate?


 ex−y=exey\ e^{x-y} = \frac{e^x}{e^y} So

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