x Turn on thread page Beta
 You are Here: Home

# Redox equations help watch

1. I'm stuck on the equation

As the oxidation state of oxygen in hydrogen peroxide is -2 + -2, and for Oxygen is 0 wouldn't I need 4 on the RHS giving

however this doesn't give an overall oxidation number of 0 on both sides only if I use 2 electrons rather than 4, it does. Could someone explain this please Thanks!
2. You need to remember that in H2O2, the oxidation number of Oxygen is actually -1, it is an exception
so itll be H2O2---O2+(2H+)+(2E-)
3. (Original post by noodlemon)
You need to remember that in H2O2, the oxidation number of Oxygen is actually -1, it is an exception
so itll be H2O2---O2+(2H+)+(2E-)
Ohh! I thought the oxygen being 2- each meant the hydrogens would be 2+ each, thanks very much!

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: April 10, 2013
Today on TSR

### University rankings 2019

Cambridge at number one

### I have imposter syndrome at Cambridge

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE