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    Hi would like some help as i am not getting the right answer in the FP2 June 2010.Here is my workings in short Name:  june 2010 Fp2.PNG
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Size:  45.7 KB.This is what the mark scheme has to say:Name:  ms.PNG
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    Thanks,
    Smith
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    (Original post by smith50)
    ...
    The limits on your integral are incorrect. What do you get at the points of intersection of the two curves?

    You will find it helpful, I think, to draw on the two areas you are subtracting to get the desired result.
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    (Original post by ghostwalker)
    The limits on your integral are incorrect. What do you get at the points of intersection of the two curves?

    You will find it helpful, I think, to draw on the two areas you are subtracting to get the desired result.

    Yes the denominators of the limits should be 18 - but how do you do the next step?
    My two coordinates of intersection was (2,pi/18) and (2,5pi/18).

    I am really stuck on the next part of the area

    smith
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    Are you confused about the part of the mark scheme that you circled? That's just the integral from whatever to whatever of 2r^2 dt evaluated...
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    Well the area is:

    \displaystyle\frac{1}{2}\int^{  \frac{5\pi}{18}}_{\frac{\pi}{18}  }(1.5+\sin 3\theta)^2-2^2\;\mathrm{d\theta}

    And if you split it into two integrals, you end up with the final term they have.
 
 
 
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