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# Trig watch

1. Hi quick question.

On D do you rearrange cos squared theta + sin squared theta = 1 to cos squared theta - 1 = sin squared theta to remove the sin squared theta from the question? I'm a little confused with it.

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3. (Original post by ThrashMetal)
Hi quick question.

On D do you rearrange cos squared theta + sin squared theta = 1 to cos squared theta - 1 = sin squared theta
That is not correct

Subtract from both sides of the equation
4. (Original post by TenOfThem)
That is not correct

Subtract from both sides of the equation
So Sin squared theta = 1-Cos squared theta? Does that mean I can now remove a sin squared theta from the original equation leaving me with 2-2 cos theta - cos squared theta = 1? I'm so confused and I don't know why.
5. (Original post by ThrashMetal)
So Sin squared theta = 1-Cos squared theta? Does that mean I can now remove a sin squared theta from the original equation leaving me with 2-2 cos theta - cos squared theta = 1? I'm so confused and I don't know why.
See post 2
6. (Original post by TenOfThem)
See post 2
Woops my bad. So basically whatever you rearrange cos^2theta+sin^2theta=1 for, you remove the = X and put brackets around what comes before the equals sign, where the = X was?
7. (Original post by ThrashMetal)
Woops my bad. So basically whatever you rearrange cos^2theta+sin^2theta=1 for, you remove the = X and put brackets around what comes before the equals sign, where the = X was?
erm

I really have no idea what you mean by this

So

8. (Original post by TenOfThem)
erm

I really have no idea what you mean by this

So

Yeah I had trouble explaining what I meant. Basically you can remove what the equation equals to and put what ever is left in brackets and solve from there is what I understand.

Thanks for the help guys, I think I fully understand it now

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Updated: April 12, 2013
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