Turn on thread page Beta
 You are Here: Home

# Integration watch

Announcements
1. Fun integration problem:

Integrate e^(x^2)
and it isn't (e^(x^2))/2x

2. I think.. but I'm not sure, that its 2xe^(x^2)
3. (Original post by Aylia)
I think.. but I'm not sure, that its 2xe^(x^2)
If you differentiate that, you get 2e^x^2 + 4x^2.e^(x^2)

You can't integrate e^(x^2) by methods you've probably learnt (ie. parts and substitution), I'm not even sure how you would do that.
4. sorry that was stupid didn't read the question properly lol
5. http://www.math.ucdavis.edu/~kouba/C...#SOLUTION%2016

Can't work out if that helps or not...
6. How about Ln?

y = e^(x^2)
ln y = x^2 ln e
ln y = x^2 ( ln e is 1 yes?)
7. (Original post by Aylia)

y = e^(x^2)
ln y = x^2 ln e
ln y = x^2 ( ln e is 1 yes?)
You can't presume Y=f(X).
8. Hm yes, I know you can integrate xe^x^2 using function and derivative, but straight e^x^2, I'll have a think.
9. (Original post by Aylia)

y = e^(x^2)
ln y = x^2 ln e
ln y = x^2 ( ln e is 1 yes?)
That's right, but you could have just missed out that middle line .
10. (Original post by Nylex)
That's right, but you could have just missed out that middle line .

yay! have spent ages thinking about that!
11. are u doing AS Level, P2?, in which case are u sure it wasn't e^(2x). If so the answer would be (1/2)e^(2x).
12. You can't integrate this directly, I'm pretty sure its called the gamma function. Between -infinity and infinity its value is root(2pi).
13. (Original post by Sir I. Newton)
You can't integrate this directly, I'm pretty sure its called the gamma function. Between -infinity and infinity its value is root(2pi).
Its not the gamma function,thats gotta do with x!.
To integrate e^x^2 u have to use a mixture of double integrals and converting from normal integration to polar integration etc etc.
Its degree level stuff(thats how u integrate the normal distribution function)
14. yipee. i remember doing htis a few weeks ago, and i've already forgotten ( ). something to do with integrating r^x e^r² between 0 and infinity.

Turn on thread page Beta
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 17, 2004
Today on TSR

### Exam Jam 2018

Join thousands of students this half term

### Solo - A Star Wars Story

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE