g(x) = ln(1 + x^2)
Find g'(x) and g''(x), hence show that x = 0 is a minimum for this
Differentiation minimum point Watch
- Thread Starter
- 12-04-2013 18:58
- 12-04-2013 19:00
What are you actually asking? You need to differentiate it twice to know whether its a min, max or point of inflection
- 12-04-2013 19:02
Have you found g'(x) and g''(x)?
- 12-04-2013 21:59
for the first derivative, that is zero where the numerator is zero....
then, differentiate again and substitute into g ''(x) the x=0 to show that (hopefully) g''(x)>0