OCR MEI AS Mathematics M1 10/06/2013

5 days is more than enough! I wish I had that much time! I only started revising yesterday...I'm in A2 and resitting...need an A in mechanics...not had much time to revise though due to synoptic papers for my other subjects! :frown:

have a feeling C4 isn't going to go too well :eek:

C4 is killing me! I can get pretty much full marks on section A but the way the questions are worded on section B makes me often wonder what I'm even supposed to be doing :tongue:

I'm resitting C3 aswell cause I got a D overall in Jan (A on coursework, U in exam :colondollar:

).

Reply 81

loua96

No problem CWE. Good luck for tomorrow everyone :redface:

(edited 10 years ago)

Reply 82

Economics247

Good luck guys and remember read the question carefully eg constant accelaration

Reply 83

Alotties

10

That was possibly the worst exam I've ever sat in my life.
I blanked completely! I've got no chance of getting a B for uni now.

Reply 84

stefanocattaneo

Original post by Alotties

That was possibly the worst exam I've ever sat in my life.
I blanked completely! I've got no chance of getting a B for uni now.

Glad I wasn't the only one... That paper was absurd.

Section A was fine, but Section B was terrible. Almost ran out of time as well :frown:

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(edited 10 years ago)

Reply 85

Alotties

10

Original post by stefanocattaneo

Glad I wasn't the only one... That paper was absurd

Posted from TSR Mobile

A girl ran out as soon as the exam finished and cried and everyone in my class (there's only 9 of us) found it hard.
I'm not too happy as I was depending on M1 to get some extra marks ahead of C3 and C4 :tongue:

Ohwell.

Reply 86

Axion

15

Lol, wtf sort of exam was that

Easily the hardest M1 paper yet

Reply 87

JG1027

hey what sort of answers did you get to the questions? this was some confusing paper :frown:

Reply 88

stefanocattaneo

Anyone want to have a go at an unofficial mark scheme?

Posted from TSR Mobile

Reply 89

jordanx

I found it ridiculously hard! Thank god I aren't the only one, ran out of time so lost 6 marks on that last question already.

Reply 90

username1209117

Worst exam of the year, want to cry :'(
hopefully the grade boundaries will be really low
no clue about the last question and first question and question five seemed too easy for 4marks and 3 marks.

having tea now to make it better

Reply 91

Jojo_555

1

Seriously. What. The. Hell.
When I first open the booklet and saw the first question on the boxes....I blanked out. Like seriously? Couldn't they give us lines instead of boxes :/
I know I've lost 12 marks for definite....
Screw mechanics :frown:

Reply 92

helpme456

Dont know why I come here, always depress myself. for the final question of section 1, v=24-18t+3t²

what was T1 and what was T2 for when it was stationary

what was the expression for x

how to prove x=20 and what was x for T2

-------

Reply 93

johnny2spoons

Original post by helpme456

Dont know why I come here, always depress myself. for the final question of section 1, v=24-18t+3t²

what was T1 and what was T2 for when it was stationary

what was the expression for x

how to prove x=20 and what was x for T2

-------

T1 was 2 and T2 was 4 by factorising v=24-18t+3t²

expression for x you had to intergrate v=24-18t+3t² to get x=t^3-9t^2+24t

and then for the last bit sub in the values of T1 and T2 into that equation

hope that helps

Reply 94

Mahinder

v=24-18t+3t^2 i differentiated the equation so i got -18+6t
at stationary it is =0 so -18+6t=0 so t=3
therefore v = -3

for the other one they said it was initaly at 0 so v=24
so i got T1=(3,-3)
T2=(0,24)
not 100% sure though

Reply 95

Axion

15

Original post by johnny2spoons

T1 was 2 and T2 was 4 by factorising v=24-18t+3t²

expression for x you had to intergrate v=24-18t+3t² to get x=t^3-9t^2+24t

and then for the last bit sub in the values of T1 and T2 into that equation

hope that helps

T1 was 2 and t2 was 4 or something

Reply 96

Jojo_555

1

Original post by helpme456

Dont know why I come here, always depress myself. for the final question of section 1, v=24-18t+3t²

what was T1 and what was T2 for when it was stationary

what was the expression for x

how to prove x=20 and what was x for T2

-------

When it is stationary, v=0
So 3t2 - 18t+24 = 0
t2-6t+8 = 0
(t-4)(t-2)
As T2>T1
T2 = 4
T1 = 2
To prove x is 20. Intergrate the equation and sub T2=4 into the equation and you'll get 20 :smile:

Reply 97

Katherineelb

Harder than any past paper I've done for sure. The only question that really gave me mental block was q7. Found it confusing , oh well now for c4!

Reply 98

JG1027

Original post by helpme456

Dont know why I come here, always depress myself. for the final question of section 1, v=24-18t+3t²

what was T1 and what was T2 for when it was stationary

what was the expression for x

how to prove x=20 and what was x for T2

-------

you first had to equate it to 0 to find the times and you would have gotten t=2 and t=4 and then integrate it to find the expression for x the displacement so i would have been 24t-9t^2+x^3+c but when t=0 the displacement is 0 so c=0 and when you plug in the numbers you got 20 and when t=4 you get 16 :confused:

hope this is right

Reply 99

johnny2spoons

Original post by Mahinder

v=24-18t+3t^2 i differentiated the equation so i got -18+6t
at stationary it is =0 so -18+6t=0 so t=3
therefore v = -3

for the other one they said it was initaly at 0 so v=24
so i got T1=(3,-3)
T2=(0,24)
not 100% sure though

no you never had to work out accelaration because when its stationary v=0 so then you just factorise 0=24-18t+3t^2 to give you t=2 and t=4

sorry :/

OCR MEI AS Mathematics M1 10/06/2013

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