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    (x+3)-9+11=0
    (x+3)+2=0
    (Of course brackets are squared)
    Can someone proof to me why the minimum coordinate is (-3,2)??


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    Use that (x+3)^2 \geq 0
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    For the x, both have (x+3) and remember that squaring any number will always be positive so the lowest number a squared number can be is 0 hence (-3+3)
    Once you get the x to the lowest number, it's a matter of just finishing off the equation to see what you get, so the 1st eq will be 0-9+11


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