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    • Thread Starter
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    solve each equation :
    a)cos^2x+3sinx-3=0

    b)3sin^2x-5cosx+2cos^2x=0

    c)3sinx-2tanx=0d)4sin^2x-5sinx+2cos^2x=0

    d)4sin^2x-5sinx+2cos^2x=0

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    PS Reviewer
    What working out have you done so far?
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    (Original post by hey_help)
    solve each equation :
    a)cos^2x+3sinx-3=0

    b)3sin^2x-5cosx+2cos^2x=0

    c)3sinx-2tanx=0d)4sin^2x-5sinx+2cos^2x=0

    d)4sin^2x-5sinx+2cos^2x=0
    You are going to need to make use of the following identities:

    \sin^2 x + \cos^2 x = 1

    \sin 2x = 2 \sin x \cos x

    \cos 2x = \cos^2 x - \sin^2 x

    \displaystyle \tan x = \frac{\sin x}{\cos x}
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    (Original post by Mr M)
    You are going to need to make use of the following identities:
    \cos 2x = \cos^2 x + \sin^2 x
    :eek4:

    Only joking
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    (Original post by Mr M)
    You are going to need to make use of the following identities:

    \sin^2 x + \cos^2 x = 1

    \sin 2x = 2 \sin x \cos x

    \cos 2x = \cos^2 x - \sin^2 x

    \displaystyle \tan x = \frac{\sin x}{\cos x}
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    (Original post by Felix Felicis)
    :eek4:

    Only joking
    Sorry!
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    (Original post by Albino)
    Et tu Albino?
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    (Original post by Mr M)
    Et tu Albino?
    beaten to it by felix but ya me too
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    (Original post by Mr M)

    \sin^2 x + \cos^2 x = 1
    darn

    too slow to mock

    serves me right for chatting on other fora
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    (Original post by TenOfThem)
    serves me right for chatting on other fora
    There are other fora?

    :eek:
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    boom shakalaka
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    (Original post by Mr M)
    There are other fora?

    :eek:
    You know about relationships now ... there are others too

    I was engaged in a Degree Classification v Student Ranking discussion

    Well exciting
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    (Original post by upthegunners)
    \displaystyle x \neq \frac{1\pm 3\sqrt 5}{2} ???
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    (Original post by Mr M)
    \displaystyle x \neq \frac{1\pm 3\sqrt 5}{2} ???
    wrong thread
 
 
 
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Updated: April 13, 2013
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