I used the following formula:
I got the x-coordinate correct but the y-coordinate I am getting wrong:
I just integrated (4x-x3)2 (between the limits 0 and 2) then multiplied by (1/8). I multiplied by 1/8 because the denominator = 2 x 4 (I found the integral of f(x) between those limits, to be 4 in earlier calculations)
My calculator does numerical integration and gets the same answer as me 128/105 but the mark scheme has 64/21 as the answer
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- Thread Starter
- 13-04-2013 21:59
- Study Helper
(Original post by GPODT)
- 13-04-2013 22:11
I just integrated (4x-x3)2 (between the limits 0 and 2) then multiplied by (1/8).
You need to square them individually, and then subtract. So, you're, in effect working out the moment from the x-axis to the upper line, and subtracting the moment from the x-axis to the curve, leaving the moment of the desired area.Last edited by ghostwalker; 13-04-2013 at 22:55.