Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    0
    ReputationRep:
    I can't understand how I got this wrong, I got A as the answer but the marking scheme say it's C, any one know what you were meant to do to get that answer, I think they have differentiated to get C but you were meant to intergrate, here is the question.


    Also what is the answer to this one I got A


    Hopefully the marking scheme is wrong and them I will have got 100% on multi choice :woop:
    Offline

    2
    ReputationRep:
    (Original post by Jack--)
    I can't understand how I got this wrong, I got A as the answer but the marking scheme say it's C, any one know what you were meant to do to get that answer, I think they have differentiated to get C but you were meant to intergrate, here is the question.


    Also what is the answer to this one I got A


    Hopefully the marking scheme is wrong and them I will have got 100% on multi choice :woop:
    eh for the first one I got A as well, to get C you differentiated. Are you sure that is the right answer?

    For the second one, I don't think it's A. To work out the centre, you do 2g = x value and 2f = y value then work it from there. If that is how you do it!
    Offline

    3
    ReputationRep:
    (Original post by Jack--)
    x
    Please try and keep questions about Higher Maths in the Higher Maths thread.

    For the first one, I get A, and since CSM gets it too, I'd assume the marking scheme is wrong.
    For the second one, a circle has the equation:  x^2 + y^2 + 2fx + 2gy + c = 0 and the centre of the circle is
    (-f,-g) so the centre of this circle is (1, -3) or A.
    Offline

    2
    ReputationRep:
    (Original post by TheFOMaster)
    Please try and keep questions about Higher Maths in the Higher Maths thread.

    For the first one, I get A, and since CSM gets it too, I'd assume the marking scheme is wrong.
    For the second one, a circle has the equation:  x^2 + y^2 + 2fx + 2gy + c = 0 and the centre of the circle is
    (-f,-g) so the centre of this circle is (1, -3) or A.
    wth I'm so confused about the second one then. I got (3,-9) which is B. Surely if you take 2g = -6, g=-3 so the x value would be 3 I'm probably doing something wrong (even though it is not my question)
    Offline

    3
    ReputationRep:
    (Original post by CSM1996)
    wth I'm so confused about the second one then. I got (3,-9) which is B. Surely if you take 2g = -6, g=-3 so the x value would be 3 I'm probably doing something wrong (even though it is not my question)
    Look at the coefficients of x^2 and y^2 in both the equation and general equation of a circle
    Offline

    2
    ReputationRep:
    (Original post by TheFOMaster)
    Look at the coefficients of x^2 and y^2 in both the equation and general equation of a circle
    omg haha i read it as x^2 and y^2 not even looking at the 3 woops
    Offline

    3
    ReputationRep:
    (Original post by CSM1996)
    omg haha i read it as x^2 and y^2 not even looking at the 3 woops
    Don't worry, I made the same mistake until glancing back at the question
    Offline

    0
    ReputationRep:
    12 is A :confused:
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brussels sprouts
    Applying to university
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.