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    (Original post by Tynos)
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    No, if you draw a line straight done from the weight and then draw a link following the direction your resolving in, it should be 5gcosalpha as usually expected

    Whats your obssession with this made up angle P? just leave P alone and focus on alpha.

    the way they've done it is a bit weird, I usually take down the plane to be 5gsin alpha (negative) and I think it should come out the same

    Resolving perpendicular does not include stuff along the plane, so you have the normal reaction force and the weight at an angle, acceleration is not included nor is tension

    Here's a diagram that may help Name:  photo (13).JPG
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    Nope. where they have 5gcosa I suppose you could alternately have 5gsinP. It's up to you really.
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    (Original post by Robbie242)
    No, if you draw a line straight done from the weight and then draw a link following the direction your resolving in, it should be 5gcosalpha as usually expected

    Whats your obssession with this made up angle P? just leave P alone and focus on alpha.

    the way they've done it is a bit weird, I usually take down the plane to be 5gsin alpha (negative) and I think it should come out the same

    Resolving perpendicular does not include stuff along the plane, so you have the normal reaction force and the weight at an angle, acceleration is not included nor is tension

    Here's a diagram that may help Name:  photo (13).JPG
Views: 63
Size:  266.3 KB (not the exact same question, but a similar principle for literally all questions)
    Ah i see now, thank you.
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    (Original post by Tynos)
    Ah i see now, thank you.
    No problem, the edexcel book is quite bad at introducing you to resolving forces tbh, it took me ages of searching to find this fact
 
 
 
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