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    Hello, the cartesian equation of a curve is y^2 = x^2 (1 - 1/4 *x^2).

    How do we find the volume from x=0 to x=2.
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    (Original post by laurawoods)
    Hello, the cartesian equation of a curve is y^2 = x^2 (1 - 1/4 *x^2).

    How do we find the volume from x=0 to x=2.
    In C4 the formula for the volume of a solid generated by an x axis rotation is
    \displaystyle \pi\int_{x_1}^{x_2} y^2 dx
    Where x_1 is the point on the left and x_2 is the point on the right. You will need to put the appropriate values in here.
    You have an equation y^2 = ... You need to substitute this into the formula and integrate between the given boundaries to find the volume.
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    (Original post by laurawoods)
    Hello, the cartesian equation of a curve is y^2 = x^2 (1 - 1/4 *x^2).

    How do we find the volume from x=0 to x=2.
    Integrate the function.
    \ I = \pi \displaystyle\int^2_0 x^2 (1 - \frac{1}{4} x^2)\ dx
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    (Original post by joostan)
    Integrate the function.
    \ I = \pi \displaystyle\int^2_0 x^2 (1 - \frac{1}{4} x^2)\ dx
    this^
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    (Original post by Goods)
    ^ this but times π. Its just a volume of revolution question. which is the integral of πr^2 dx between 2 and 0
    Yeah, I missed the pi due to a Latex problem but it's in now
 
 
 
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