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    can anyone help with this Q!
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    (Original post by jopkins)
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    can anyone help with this Q!
    What can't you do? It's a pretty standard question. The first part is as simple as it gets.
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    How do you find the y cord
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    (Original post by jopkins)
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    can anyone help with this Q!
    a) 1 mark using m=m, (2a,0)

    Set up a straight line equation y-y_1=m(x-x_1)

    b) Simultaneously solve y^2=4ax and your other straight line equation, then don't forget its the midpoint, so once you have P and Q find the midpoint of the two points, R

    c) is beyond my knowledge

    d) Sub your coordinates of Rinto the parabola, you should get m to cancel out, once you've done this you can solve for a, the focus of the parabola is denoted as S(a,0) and the directrix is x=-a (the reason you sub R in, is to cancel the x and y, and to not leave a=0)
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    thats FP1 not FP2
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    (Original post by study beats)
    thats FP1 not FP2
    No, that's FP2 it involves Locus, different exam boards have different material.
 
 
 
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